@drmilun9,
hajde posalji kompletan kod tog view fajla. Ovo radi van codeignitera, samostalno, sa jednom test php stranom na koju saljes podatak/izabranu opciju, bez problema...
Code:
<script src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
<script type="text/javascript">
function dynamic_Select(dropdown) {
$.ajax({
type: "POST",
url: "http://localhost/test.php",
data:'name='+ dropdown,
success: function(data){ alert(data); }
});
}
</script>
<body>
<form action="" method="post">
<select name="dropdown" id="dropdown" onchange="dynamic_Select(this.value)">
<option value="">Select</option>
<option value="patka">Patka</option>
<option value="konj">Konj</option>
</select>
</form>
</body>
Test.php
Code:
<?php
echo $_POST['name'];
?>